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if the electron in hydrogen orbit jumps...

if the electron in hydrogen orbit jumps form third orbit to second orbit, the wavelength of the emitted radiation is given by

A

`lamda=36/(5R)`

B

`lamda=(5R)/(36)`

C

`lamda=5/R`

D

`lamda=R/6`

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The correct Answer is:
A
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Knowledge Check

  • If the electron in the hydrogen atom jumps from third orbit to second orbit the wavelength of the emitted radiation in term of Rydberg constant is

    A
    `(6)/(5R)`
    B
    `(36)/(5R)`
    C
    `(64)/(7R)`
    D
    None of these

  • If an electron in hydrogen atom jumps from third orbit to second orbit, the frequency of the emitted radiation is given by (c is speed of light )

    A
    `"3Rc"/29`
    B
    `"5Rc"/36`
    C
    `"7Rc"/36`
    D
    `"8Rc"/31`

  • When the electron in a hydrogen atom jumps from the second orbit to the first orbit , the wavelength of the radiation emitted is lamda . When the electron jumps from the third orbit to the first orbit , of the same atom , the wavelength of the emitted radiation would be

    A
    `27/32 lamda`
    B
    `32/27 lamda`
    C
    `2/3 lamda`
    D
    `3/2 lamda`
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