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A solution set of the equations x+2y+z=1...

A solution set of the equations `x+2y+z=1`, `x+3y+4z=k`, `x+5y+10z=k^(2)` is

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The correct Answer is:
K=1,2
k=1,x=5t+1,y=-3t,z=t `t in R`
k=2,x=5t-1,y=1-3t,z=t
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