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Two short bar magnets of length 1cm each...

Two short bar magnets of length `1cm` each have magnetic moments `1.20 Am^(2) and 1.00 Am^(2)` respectively. They are placed on a horizontal table parallel to each other with their `N` poles pointing towards the south. They have a common magnetic equator and are separted by a distance of `20.0 cm`. The value of the resultant horizontal magnetic induction at the mid - point `O` of the line joining their centres is close to (Horizontal component of earths magnetic induction is `3.6 xx 10.5 Wh//m^(2)`

A

`3.6xx10^(-5)Wb//m^(2)`

B

`2.56xx10^(-4)Wb//m^(2)`

C

`3.50xx10^(-4)Wb//m^(2)`

D

`5.80xx10^(-4)Wb//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
2

`B_("net")=B_(1)+B_(2)+B_(H)`
`B_("net")mu_(0)/(4pi)((M_(1)+M_(2)))/r^(3)+B_(H)`
`=(10^(-7)(1.2+1))/(0.1)^(3)+3.6xx10^(-5)=2.56xx10^(-4) wb//m^(2)`
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