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Calculate the magnetic moment of a thin wire with a current `I=0.8 A`, wound tightly on half a toroid (figure).the diameter of the cross-section of the tore is equal to `d=5.0 cm`,the number of turns is `N=500`.

Text Solution

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The correct Answer is:
`1/2 A.m^(2)`
`M=underset(theta=0)overset(pi)intdMsintheta`
`=underset(theta=0)overset(pi)int (dN) .i.A. sintheta =underset(0)overset(pi)int N/pi _|_ ((pd^(2))/4) sin theta d theta `
`M=1/2N.i.d^(2) rArr M=1/2(Amp m^(2))`
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Calculating the magnetic moment ( in Am^2 ) of a thin wire with a current I=8A, wound tightlly on a half a tore (see figure). The diameter of the cross section of the tore is equal to d=5cm, and the number of turns is N=500.

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