Electron drift speed is estimated to be only a few mm/s for currents in the range of few amperes ? How then is current established almost the instant a circuit is closed.

(a) In Example 3.1, the electron drift speed is estimated to be only a few mm s^(-1) for currents in the range of a few amperes? How then is current established almost the instant a circuit is closed? (b) The electron drift arises due to the force experienced by electrons in the electric field inside the conductor. But force should cause acceleration. Why then do the electrons acquire a steady average drift speed? (c) If the electron drift speed is so small, and the electron’s charge is small, how can we still obtain large amounts of current in a conductor? (d) When electrons drift in a metal from lower to higher potential, does it mean that all the ‘free’ electrons of the metal are moving in the same direction? (e) Are the paths of electrons straight lines between successive collisions (with the positive ions of the metal) in the (i) absence of electric field, (ii) presence of electric field?

Electron drift speed is estimated to be of the order of mm s^(-1) . Yet large current of the order of few amperes can be set up in the wire. Explain briefly.

Assertion: Drift velocity of electrons developed in a current-carrying conductor is of the order of 10^(-4) m//s but current in the conductor is established almost instantly the switch is closed. Reason: Electric field in a conductor sets up with the speed of light.

Is drift speed of electrons in a conductor carrying current the same as the speed of current ?

In adjacent circuit, switch S is closed at t = 0. The time at which current in the circuit becomes half of the steady current is