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In a p-n junction, width of depletion re...

In a p-n junction, width of depletion region is 300 nm and electric field of `7 xx 10^(5) V//m` exists in it.
(i) Find the height of potential barrier.
(ii) What should be the minimum kinetic energy of a conduction electron which can diffuse from the n-side to the p-side?

Text Solution

Verified by Experts

(i) `V=Ed = 7 xx 10^(5) xx 300 xx 10^(-9)= 0.21 V`
(ii) Kinetic energy =eV = 0.21 eV
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The width of depletion region in a P-N junction diode is 500 nm and an intense electric field of 5xx10^(5)Vm^(-1) is also found to exit init. Determine the height of the potential barrier. Also calculate the kinetic energy which a conduction electron must have inorder to diffuse from the n-side to p-side.

Knowledge Check

  • The width of depletion region in p-n junction diode is 500 nm and an intrinsic electric field of 6xx 10^(5) Vm^(-1) is also found to exist in it. What is the kinetic energy which a conduction electron must have in order to diffuse from the n-side to p-side?

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