How many electrons must be added to one plate and removed from the other so as to store 25.0 J of energy in a 5.0 nF parallel plate capacitor?

Explanation

To find out how many electrons must be added to one plate and removed from the other to store 25.0 J of energy in a 5.0 nF parallel plate capacitor, we can follow these steps:

### Step 1: Use the formula for energy stored in a capacitor
The energy (U) stored in a capacitor is given by the formula:
\[ U = \frac{Q^2}{2C} \]
where \(U\) is the energy, \(Q\) is the charge, and \(C\) is the capacitance.
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