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An oil drop of mass m carrying charge...

An oil drop of mass ` m` carrying charge - Q is to be held stationary in the gravitational field of the earth. What is the magnitude and direction of the electrostatic field required for this purpose ?

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To solve the problem of holding an oil drop of mass \( m \) carrying charge \( -Q \) stationary in the gravitational field of the Earth, we need to analyze the forces acting on the drop. ### Step-by-Step Solution: 1. **Identify the Forces Acting on the Oil Drop**: - The oil drop experiences a gravitational force acting downward, which is given by: \[ F_g = mg ...
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Knowledge Check

  • What is the magnitude and direction of the magnetic field at point B ?

    A
    `3.3xx10^(-5)` T, clockwise
    B
    `6.8xx10^(-5)` T, counterclockwise
    C
    `3.3xx10^(-5)` T, counterclockwise
    D
    `2.7xx10^(-4)` T, clockwise

  • What is the magnitude and direction of the magnetic field at point A ?

    A
    `3.3xx10^(-5)` T, clockwise
    B
    `6.8xx10^(-5)` T, counterclockwise
    C
    `3.3xx10^(-5)` T, counterclockwise
    D
    `2.7xx10^(-4)` T, clockwise

  • In Q.30, the magnitude and direction of magnetic field will be

    A
    `2.5 muT` in X-direction
    B
    `2.5 muT` in Y-direction
    C
    `2.5 muT` in Z-direction
    D
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