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A body is thrown with a velocity of 9.8 ...

A body is thrown with a velocity of `9.8 m//s` making an angle of `30^(@)` with the horizontal. It will hit the ground after a time

A

3s

B

2s

C

1.5s

D

1s

Text Solution

Verified by Experts

The correct Answer is:
D
`T=(2u sin theta)/(g)=(2xx9.8sin 30^(@))/(9.8)=1` sec
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