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The ratio of the de Broglie wavelength ...

The ratio of the de Broglie wavelength of a proton and alpha particles will be `1:2` if their

A

velocity are in the ratio `1:8`

B

velocity are in the ratio `8:1`

C

kinetic energy are in the ratio `1:64`

D

kinetic energy are in the ratio `1:256`

Text Solution

Verified by Experts

The correct Answer is:
B
`lambda=v`
then `lambda=h/(mV)` or `lambda^(2)=h/m` So, `lambda=sqrt(h/m)`
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Knowledge Check

  • The ratio of the wavelength of a proton & alpha -particle will be 1:2 if their

    A
    Velocity of proton to velocity of `alpha` is in ratio 1:8
    B
    Velocity of proton of velocity of `alpha` particle is in the ratio 8:1
    C
    Kinetic energy of proton to Kinetic energy of `alpha` particle is in the ratio 64:1
    D
    Kinetic energy of proton to kinetic energy of `alpha` particle is in the ratio 26:1

  • The ratio of de broglie wavelength of a proton and an alpha particle moving with the same velocity is

    A
    1
    B
    2
    C
    4
    D
    0.25

  • Find the ratio of de Broglie wavelength of a proton and as alpha -particle which have been accelerated through same potential difference.

    A
    `2sqrt2:1`
    B
    `3:2`
    C
    `3sqrt2:1`
    D
    `2:1`

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