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Consider an electron in the n^(th) orbit...

Consider an electron in the `n^(th)` orbit of a hydrogen atom in the Bohr model . The circumference of the orbit can be expressed in terms of the de Broglie wavelength `lambda` of the electron as :

A

`(0.529) n lambda`

B

`sqrt(n) lambda`

C

`(13.6) lambda`

D

`n lambda`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Consider an electron in the nth orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength lambda of that electron as

    A
    `(0.259)n lambda`
    B
    `sqrt(n) lambda`
    C
    `(13.6) lambda`
    D
    `n lambda`

  • The circumfernce fo n^(th) orbit in H-atom can be expressed in tems fo de.Broglie wavelngth lambda as :

    A
    ` sqrt ( nlambda)`
    B
    `n lambda`
    C
    `0. 529 h lambda`
    D
    13. 6 lambda`

  • Consider an electron in the nth orbit of a hydrogen atom in the Bohr's model. In terms of de-Broglie wavelength of that electron the circumference of the orbit is given as .

    A
    `0.259 n lambda`
    B
    `sqrt(n ) l`
    C
    `13.6 lambda`
    D
    `n lambda`

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    If the de Broglie wave length of the fourth Bohr's orbit of hydrogen atom is 4 Å, the circumference of the orbit is:

    The relation between the circumference of an electron orbit in a hydrogen atom and the de Broglie wavelength of the electron in the same orbit is given by

    The relation between the circumference of an electron orbit in a hydrogen atom and the de broglie wavelength of the electron in the same orbit is given by

    The circumference of the third Bohr orbit of an electron is 4.5xx10^(-9) m . What is the de broglie wavelength of the electron in this orbit ?

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