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An electron in a hydrogen like atom make...

An electron in a hydrogen like atom makes transition from a state in which itd de Broglie wavelength is `lambda_(1)` to a state where its de Broglie wavelength is `lambda_(2)` then wavelength of photon (`lambda`) generated will be :

A

`lambda=lambda_(1)-lambda_(2)`

B

`lambda=(4mc)/(h){(lambda_(1)^(2)lambda_(2)^(2))/(lambda_(1)^(2)-lambda_(2)^(2))}`

C

`lambda=sqrt((lambda_(1)^(2)lambda_(2)^(2))/(lambda_(1)^(2)-lambda_(2)^(2)))`

D

`lambda=(2mc)/(h){(lambda_(1)^(2)lambda_(2)^(2))/(lambda_(1)^(2)-lambda_(2)^(2))}`

Text Solution

Verified by Experts

The correct Answer is:
D
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