Calculate the amount of heat evolved during the complete combustion of 100 ml liquid benzene from the following data :
18 gm of graphite on complete combustion evolve 590 kJ heat
15889 kJ heat required to dissociate all the molecules of 1 liter water into `H_(2)` and `O_(2)`
The heat of formation of liquide benxene is `50kJ//"mol"`
Density of `C_(6)H_(6)(l)=0.87gm//ml`

Explanation

(i) `C(s)+O_(2)(g)rarrCO_(2)(g), DeltaH_(f)^(@)= -393.33 KJ//mol`
(ii) `H_(2)(g)+(1)/(2)O_(2)(g)rarrH_(2)O(l), Delta H_(f)^(@)= -286 KJ//mol`
(iii) `C_(6)H_(6)(l)+(15)/(2)O_(2)(g)rarr6CO_(2)(g)+3H_(2)O(l)`
`:. DeltaH^(@)=[6(-393.33)+3(-286)]-50=-3268 KJ//"mole"`
`:.` Heat evolved from `87 g` benzene `3645 KJ`