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What will be the emf for the given cell ...

What will be the emf for the given cell ?
`Pt|H_(2)(g,P_(1))|H^(+)(aq)|H_(2)(g,P_(2))|Pt`

A

`(RT)/(F)log_(e)(p_(1))/(p_(2))`

B

`(RT)/(2F)log_(e)(p_(1))/(p_(2))`

C

`(RT)/(F)log_(e)(p_(2))/(p_(1))`

D

`(RT)/(2F)log_(e)^(p_(2))/(p_(1))`

Text Solution

Verified by Experts

The correct Answer is:
B
The `E^(@)` of cell will be zero.
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Knowledge Check

  • What will be the emf for the given half cell Pt|H_(2)(P_(1)|H^(+)(aq)|H_(2)(P_(2))|Pt

    A
    `(RT)/(F)` in `(p_(1))/(p_(2))`
    B
    `(RT)/(2F)` in `(p_(1))/(p_(2))`
    C
    `(RT)/(F)` in `(P_(2))/(P_(1))`
    D
    none of these

  • What will be the e.m.f. of the given cell? Pt|H_(2)(P_(1))|H^(+)(aq)|H_(2)(P_(2))|Pt

    A
    `(RT)/(F)"ln"(P_(1))/(P_(2))`
    B
    `(RT)/(2F)"ln"(P_(1))/(P_(2))`
    C
    `(RT)/(F)"ln"(P_(2))/(P_(1))`
    D
    none of these

  • What will be the emf for the given cell Pt|H_(2)(P_(1))|H_((aq))^(+)||H_(2)(P_(2))|Pt

    A
    `(RT)/(f)ln(P_(1))/(P_(2))`
    B
    `(RT)/(2f)ln(P_(1))/(P_(2))`
    C
    `(RT)/(f)ln(P_(2))/(P_(1))`
    D
    None of these
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