Home
Class 12
PHYSICS
If acceleration of particle changing wit...

If acceleration of particle changing with time is a = (4t-2) `m//s^(2)` during one dimensional motion find change in velocity between (t = 0 sec) to t = 2 sec.

A

`4 m//s`

B

`2 m//s`

C

`6 m//s`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(v_(1))overset(v_(2))intdv=underset(0)overset(2)int(4t-2)dt`
`Deltav=v_(2)-v_(1)=4m//s`
Promotional Banner

Topper's Solved these Questions

  • REVIEW TEST

    VIBRANT|Exercise PART - II : PHYSICS|262 Videos

  • TEST PAPERS

    VIBRANT|Exercise PART - II : PHYSICS|56 Videos

Similar Questions

Explore conceptually related problems

The acceleration of paticle varies with time as : a(t) = 3t^(2) +4 If the initial velocity of particle is 2 m//s , find the velocity of particle at t = 3sec .

Power applied to a particle varies with time as P=(4t^(3)-5t+2) watt, where t is in second. Find the change its K.F. between time t = 2 and t = 4 sec.

The acceleration of a particle varies with time t as a=t^(2)+t+2 where t is in seconds. The particle starts with an initial velocity v-3m/s at t=0. find the velocity of the particle at the end of 5s.

Position of a particle at any instant is given by x = 3t^(2)+1 , where x is in m and t in sec. Its average velocity in the time interval t = 2 sec to t = 3 sec will be :

During one dimensional motion on x-axis Velocity time graph for particle is given. Average acceleration between (t = 0 sec) to (t = 6 sec)

The acceleration of a particle is given by, a = t/6 at t = 0, velocity v = 2 m/s, displacement s= 2m. Find the velocity at t= 4 seconds,

Acceleration of a paritcle moving in x-y plane varies with time t as. vec(a) = (ti + 3T^(2)j) . Here a is in m//s^(2) and t in sec. At time t = 0 particle is at rest origin. Mass of the particles is 1 kg . Find the net work done on the particle in first 2 sec .

(a) If s = 2t^(3)+ 3t^(2) + 2t + 8 then find time at which acceleration is zero. (b) Velocity of a particle (starting at t =0) varies with time as v= 4t. Calculate the displacement of part between t = 2 to t = 4 s

VIBRANT-REVIEW TEST-PART - II : PHYSICS
  1. Force vec(F)=(4sqrt(2hat(i))+3sqrt(2)hat(j)) acting on a body so that ...

    Text Solution

    |

  2. Two forces 10 N and 15 N are acting on a body then which cannot be the...

    Text Solution

    |

  3. If acceleration of particle changing with time is a = (4t-2) m//s^(2) ...

    Text Solution

    |

  4. Young modulus of steel is 3 xx 10^(11) N//m^(2). When expressed in C.G...

    Text Solution

    |

  5. If momentum P, area A and time T are selected as fundamental quantitie...

    Text Solution

    |

  6. Two forces are acting on body vec(F)(1)=-(50-t^(2))hat(j) Newton and v...

    Text Solution

    |

  7. In the given velocity v//s position graph find acceleration at x = 2m

    Text Solution

    |

  8. Select correct statements

    Text Solution

    |

  9. If x = (4t^(2)+2) any y = 2t, then find ((dx)/(dy)) at t = 2 sec. (x i...

    Text Solution

    |

  10. Which of the following cannot be the group of fundamental quantities. ...

    Text Solution

    |

  11. Statement-1 : Using dimensional analysis we can drive only those formu...

    Text Solution

    |

  12. If side length of cube changing at 0.1mm//sec. Then what will be rate ...

    Text Solution

    |

  13. During one dimensional motion on x-axis Velocity time graph for partic...

    Text Solution

    |

  14. During one dimensional motion on x-axis Velocity time graph for partic...

    Text Solution

    |

  15. During one dimensional motion on x-axis Velocity time graph for partic...

    Text Solution

    |

  16. Particle running with constant speed v in circle of radius R then answ...

    Text Solution

    |

  17. Particle running with constant speed v in circle of radius R then answ...

    Text Solution

    |

  18. A particle is performing one dimensional motion on x-axis and it's x-c...

    Text Solution

    |

  19. A particle is performing one dimensional motion on x-axis and it's x-c...

    Text Solution

    |

  20. A particle is performing one dimensional motion on x-axis and it's x-c...

    Text Solution

    |