A conical flask of mass 10 kg and base area `10^(3)cm^(2)` is floating in liquid of specific gravity 1.2 as shown in figure. The force that liquid exerts on curved surface of conical flask is 10x newton (Neglect the atmospheric pressure and take g = 10 `m//s^(2)`) then the value of x is

Answer

2

Explanation

By work energy theorem
`(mg sintheta)l+(mgsintheta-mu mg costheta)lambdal-0`
`implies sin theta+lambda(sintheta-3sin theta)=0`
`implies sin theta = 2 lambda sin theta`
`implies lambda=(1)/(2)`
`thereforen=2`