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In a lattice of X and Y atoms, If X atom...

In a lattice of X and Y atoms, If X atoms are present at corners and Y atoms at the body centre & one X atom is removed from a corner from each unit cell, then the formula of the compound will be:

A

`X_(7)Y`

B

`X_(8)Y_(7)`

C

`X_(7)Y_(8)`

D

`X_(7)Y_(7)`

Text Solution

Verified by Experts

The correct Answer is:
C
At corner `= (1)/(8)` (for per atom)
`rArr X_(1 - (1)/(8)) Y` (one X atom removed)
`rArr X_(7//8)y`
`rArr x_(7)y_(8)`
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Knowledge Check

  • In a fcc arrangement of P and Q atoms, where P atoms are at the corners of the unit cell, Q atoms at the face centres and two atoms are missing from two corners in each unit cell, then the formula of the compound is

    A
    `P_2Q_3`
    B
    `P_4Q`
    C
    `P_4Q_5`
    D
    `PQ_4`

  • In a f.c.c. arrangement of A and B atoms, where A atoms are at the corners of the unit cell and B atoms at the face - centres, one of the A atom is missing from one corner in each unit cell. The formula of compound is :

    A
    `A_(24)B_(7)`
    B
    `A_(7)B_(24)`
    C
    `A_(7)B_(28)`
    D
    `A_(28)B_(7)`

  • In foc arrangement of A and B atoms, where A atoms are at the corners of the unit cell, B atoms at the face centres, two atoms are missing from two corners in each unit cell, then the simplest formula of the compound is

    A
    `A_7B_6`
    B
    `A_6B_7`
    C
    `A_7B_(24)`
    D
    `AB_4`
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