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Which is the number of valence electrons...

Which is the number of valence electrons in :
(a) sodium ion, `Na^(+)`
(b) oxide ion, `O^(2-)`

Text Solution

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(i) sodium ion `(Na^(+))`
No of electrons : (11-1)=10 , Electronic configuration =2,8
`therefore Na^(+)` ion has 8 valence electrons
(ii) Oxide ion `(O^(-))`
No of elctrons: (8+2)=10 , Electronic configuratino =2,8
`therefore O^(2-)` ion has 8 valence electrons.
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Knowledge Check

  • The number of valence electrons in the O^(2-) ion is

    A
    4
    B
    6
    C
    8
    D
    10

  • Number of valence electrons in Cl^(-) ion are

    A
    16
    B
    8
    C
    17
    D
    18

  • The number of valence electrons in a sulphide ion, S^(2-) is :

    A
    16
    B
    10
    C
    9
    D
    8

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