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For a planet the escape velocity (v) of ...

For a planet the escape velocity (v) of a body depends upon the radius ( R) of the planet and acceleration due to gravity (g) . Establish a relation among the above physical quantities.

Text Solution

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The correct Answer is:
v = `k sqrt(gR)`
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Knowledge Check

  • The mass of a planet is 4 times the mass of the earth and its radius is 2 times the radius of the earth. The acceleration due to gravity on that planet is

    A
    `9.8 m*s^(-2)`
    B
    `19.6 m*s^(-2)`
    C
    `4.9 m*s^(-2)`
    D
    `39.2 m*s^(-2)`

  • Imagine a new planet having the same density as that of earth but it is 3 times bigger than the earth in size. if the acceleration due to gravity on the surface of earth is g and that on the new planet is g^’ , then

    A
    `g^' = 3g`
    B
    `g^' = 9g`
    C
    `g^' = g/g`
    D
    `g^' = 27g`

  • Which of the following quantities is dimensionless if v = speed , r = radius of a circular path and g = acceleration due to gravity?

    A
    `(v^(2)r)/(g)`
    B
    `v^(2)/(rg)`
    C
    `(v^(2)g)/(r)`
    D
    `v^(2)`rg

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    If both the radius and the mean density of a planet are half the radius and the mean density of the earth, what will be the acceleration due to gravity on the surface of that planet ? Given that the acceleration due to gravity on the earth's surface =980 cm*s^(-2)

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