If the force acting on a body at time t ...

If the force acting on a body at time t is F = `at^(-1)+bt^(2)` then find out the dimensions of a and b.

Answer

Step by step text solution for If the force acting on a body at time t is F = at^(-1)+bt^(2) then find out the dimensions of a and b. by PHYSICS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Topper's Solved these Questions

MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY
CHHAYA PUBLICATION|Exercise Problem Set -I (Based on Dimensional Analysis )|6 Videos
MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY
CHHAYA PUBLICATION|Exercise Problem Set -I (Based on Measurement )|8 Videos
MEASUREMENT AND DIMENSION OF PHYSICAL QUANTITY
CHHAYA PUBLICATION|Exercise Short Answer Type Questions -I|6 Videos
KINETIC THEORY OF GASES
CHHAYA PUBLICATION|Exercise CBSE Scanner|9 Videos
NATURE OF VIBRATION
CHHAYA PUBLICATION|Exercise EXERCISE (CBSE SCANNER)|2 Videos

A force F is given by F =a+bt^2 in terms of time t. The dimension of a and b are.

`[MLT^(-1)]` and `[MLT^(-2)]`

`[ML^0 T^1]` and `[MLT^2]`

`[M^0 LT^(0-1)]` and `[M^0 L^0 T^2]`

`[MLT^(-2)]` and `[MLT^(-4)]`

The velocity of a particle in time t is v = at + (b)/(t+c) . The dimension of a, b and c are

`L^(2)`, T, LT

`LT^(-2)`,L,T

`LT^(2)`,LT,L

L,LT,`T^(2)`

If force (F) ,velocity(V) and time (T) are taken as fundamental units,then the dimensions of mass are

`[FVT^-1]`

`[FVT^-2]`

`[FV^-1T^-1]`

`[FV^-1T]`