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When a sample of Baking soda is strongly...

When a sample of Baking soda is strongly ignited in a crucible it suffered a loss in weight of 3.1 g. The mass of baking soda is

A

16.8 g

B

8.4 g

C

11.6 g

D

4.2 g

Text Solution

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The correct Answer is:
To solve the problem of determining the mass of baking soda that suffered a loss in weight of 3.1 g when strongly ignited, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Chemical Formula of Baking Soda:** - Baking soda is chemically known as sodium bicarbonate, and its formula is NaHCO₃. 2. **Understand the Decomposition Reaction:** - When sodium bicarbonate is heated, it decomposes into sodium carbonate (Na₂CO₃), water (H₂O), and carbon dioxide (CO₂). - The balanced chemical equation for this reaction is: \[ 2 \text{NaHCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{H}_2\text{O} + \text{CO}_2 \] 3. **Calculate Molar Masses:** - Molar mass of NaHCO₃ (sodium bicarbonate) = 23 (Na) + 1 (H) + 12 (C) + 3*16 (O) = 84 g/mol. - Molar mass of Na₂CO₃ (sodium carbonate) = 2*23 (Na) + 12 (C) + 3*16 (O) = 106 g/mol. - Molar mass of H₂O (water) = 2*1 (H) + 16 (O) = 18 g/mol. - Molar mass of CO₂ (carbon dioxide) = 12 (C) + 2*16 (O) = 44 g/mol. 4. **Determine Total Mass Loss:** - From the balanced equation, we see that 2 moles of NaHCO₃ produce 1 mole of Na₂CO₃, 1 mole of H₂O, and 1 mole of CO₂. - The total mass loss during the decomposition is the sum of the masses of water and carbon dioxide produced: \[ \text{Mass loss} = \text{mass of H}_2\text{O} + \text{mass of CO}_2 = 18 \text{ g} + 44 \text{ g} = 62 \text{ g} \] 5. **Relate Mass Loss to Initial Mass of Baking Soda:** - If 62 g of baking soda results in a loss of 3.1 g, we can set up a proportion to find the initial mass of baking soda (let's call it \( x \)): \[ \frac{62 \text{ g}}{168 \text{ g}} = \frac{3.1 \text{ g}}{x} \] 6. **Calculate the Initial Mass of Baking Soda:** - Cross-multiplying gives: \[ 62x = 3.1 \times 168 \] - Calculate \( 3.1 \times 168 = 520.8 \). - Now, divide by 62: \[ x = \frac{520.8}{62} \approx 8.4 \text{ g} \] 7. **Final Answer:** - The mass of baking soda is approximately **8.4 g**.

To solve the problem of determining the mass of baking soda that suffered a loss in weight of 3.1 g when strongly ignited, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Chemical Formula of Baking Soda:** - Baking soda is chemically known as sodium bicarbonate, and its formula is NaHCO₃. 2. **Understand the Decomposition Reaction:** ...
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Knowledge Check

  • When a sample of Baking soda is strongly ignited in a crucible it suffered a loss in weight of 3.1g . The mass of baking soda is

    A
    `16.8g`
    B
    `8.4g`
    C
    `11.6g`
    D
    `4.2g`
  • Formula of baking soda is

    A
    `NH_(4) CO_(3)`
    B
    `NaHCO_(3)`
    C
    `Na_(2) CO_(3)`
    D
    `(NH_(4) )_(2) CO_(3)`
  • Formula of Baking soda is

    A
    `NaOH `
    B
    `NaHCO_3`
    C
    `NaCl`
    D
    `Na_2CO_3, 10 H_2O`
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