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The correct of decreasing second ionisat...

The correct of decreasing second ionisation enthalpy of `Ti(22),V(23),Cr(24)` and `Mn(25)` is

A

`Ti gt V gt Cr gt Mn`

B

`Cr gt Mn gt V gt Ti`

C

`V gt Mn gt Cr gt Ti`

D

`Mn gt Cr gt Ti gt V`

Text Solution

Verified by Experts

The correct Answer is:
B
Ionisation energy from left to right in a period increases. In all the ions the `2^(nd)` electro are being eliminated from 4s orbital
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Knowledge Check

  • The correct order of decreasing second ionization enthalpy of Ti(22) , V(23) , Cr(24) , and Mn(25) is :

    A
    `Ti gt V gt Cr gt Mn`
    B
    `Cr gt Mn gt V gt Ti`
    C
    `V gt Mn gt Cr gt Ti`
    D
    `Mn gt Cr gt Ti gt V`

  • The correct order of decreasing second ionization enthalpy of Ti(22) , V(23) , Cr(24) , and Mn(25) is :

    A
    `Ti gt V gt Cr gt Mn`
    B
    `Cr gt Mn gt V gt Ti`
    C
    `V gt Mn gt Cr gt Ti`
    D
    `Mn gt Cr gt Ti gt V`

  • The second ionisation enthalpy is

    A
    smaller than the first ionisation enthalpy
    B
    almost equal to the first ionisation enthalpy
    C
    smaller than the third ionisation enthalpy
    D
    equal to the second electron gain enthalpy.

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