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The equation of the circle in the first ...

The equation of the circle in the first quadrant touching each co-ordinate axis at a distance of one unit from the origing is :

A

`x^(2) + y^(2) - 2x - 2y + 1 = 0 `

B

`x^(2) + y^(2) - 2x - 2y - 1 = 0 `

C

`x^(2) + y^(2) - 2x - 2y = 0 `

D

`x^(2) + y^(2) - 2x + 2y - 1 = 0 `

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The equation of the circle in the third quadrant touching each co-ordinate axis at a distance of 2 units from the origin is

    A
    `(X-2)^(2) + (y-2)^(2) = (2)^(2)`
    B
    `(x+2)^(2) + (y+2)^(2) = 4`
    C
    `(x+2)^(2) + (y+2)^(2) = 2`
    D
    `(x-2)^(2) + (y-2)^(2) = 2`

  • The equation of the circle in the first quadrant which touches each axis at a distance 5 from the origin, is

    A
    `X ^(2) + Y^(2) + 5X + 5Y + 25 =0`
    B
    ` X ^(2) + Y^(2) -10x -10y +25 =0`
    C
    `x ^(2) + y^(20)-5x-5y + 25 =0`
    D
    `x ^(2) + y^(2) + 10 x + 10 y + 25 =0`

  • The equation to the circle whose radius is 4 and which touches the negative x-axis at a distance 3 units from the origin is

    A
    `x^(2) + y^(2) + 6x + 8y - 9 = 0`
    B
    `x^(2) + y^(2) +- 6x - 8y + 9 = 0`
    C
    `x^(2) + y^(2) + 6x +- 8y + 9 = 0`
    D
    `x^(2) + y^(2) +- 6x - 8y - 9 = 0`

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    Find the equation of a circle Which touches both the axes at a distance of 6 units from the origin.Which touches x-axis at a distance 5 from the origin and radius 6units Which touches both the axes and passes through the point (2,1) Passing through the origin,radius 17 and ordinate of the centre is -15.

    The differential equation of all circles in the first quadrant which touch the coordiante axes is of order

    The equation of the circle of radius 5 and touching the coordinates axes in third quadrant, is

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