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The molar solubility of lead iodate, Pb(...

The molar solubility of lead iodate, `Pb(IO_3)_2` is `4.0xx10^(-5)` mol/L at `25^@C` . Calculate its `K_(sp)`.

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To calculate the solubility product constant (Ksp) of lead iodate, `Pb(IO_3)_2`, given its molar solubility, follow these steps: ### Step 1: Write the Dissociation Equation Lead iodate dissociates in water according to the following equation: \[ Pb(IO_3)_2 (s) \rightleftharpoons Pb^{2+} (aq) + 2 IO_3^{-} (aq) \] ### Step 2: Define Molar Solubility ...
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Knowledge Check

  • The solubility of Sb_(2)S_(3) in water is 1.0 xx 10^(-5) mol/letre at 298K. What will be its solubility product ?

    A
    `108 xx 10^(-25)`
    B
    `1.0 xx 10^(-25)`
    C
    `144 xx 10^(-25)`
    D
    `126 xx 10^(-24)`

  • The solubility of CuBr is 2 xx 10^(-4) mol/at 25^(@)C . The K_(sp) value for CuBr is

    A
    `4 xx 10^(-8) mol^(2) l^(-2)`
    B
    `4 xx 10^(-11) mol^(2) L^(-1)`
    C
    `4 xx 10^(-4) mol^(2) l^(-2)`
    D
    `4 xx 10^(-15) mol^(2) l^(-2)`

  • The solubility of BaSO_4 in water is 2.42xx10^(-3) gL^(-3) at 298 K. The value of its solubility product ( k_(sp) ) will be (Given molar mass of BaSO_4= 233 g mol^(-1) )

    A
    `1.08xx10^(-10) mol^2 L^(-2)`
    B
    `1.08xx10^(-12) mol^2 L^(-2)`
    C
    `1.08xx10^(-8) mol^2 L^(-2)`
    D
    `1.08xx10^(-14) mol^2 L^(-2)`
    • MODERN PUBLICATION-EQUILIBRIUM-Revision Exercise (Numerical Problems )
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    7. The equilibrium constant K(p) of the reaction: 2SO(2)+O(2) hArr 2SO(3)...

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    8. The molar solubility of lead iodate, Pb(IO3)2 is 4.0xx10^(-5) mol/L a...

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