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PEARSON IIT JEE FOUNDATION-EXPRESSIONS AND SPECIAL PRODUCTS -Assessment Tests (Test 2)
- Factorise 25x^(2) - 30xy + 9y^(2). The following steps are involved ...
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- The following steps are involved in finding the value of 100 (3)/(4) x...
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- If x^(2) + 8x+ k is a perfect square , then find the value of k .
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- If x + (1)/(x) = 2 then x^(2010) + x^(2009) = "".
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- (3x - 4y)^(2) - (4x + 3y)^(2) = "".
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- The HCF of 44 x^(5) y^(4) , 88 x^(6) y^(5) , and 66x^(7) y^(6) "".
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- Factorise x^(4) + x^(3) - x^(2) - x.
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- (a^(4) - a^(2)) + (a^(3) + a^(2)) = "".
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- If x - (1)/(2x) = 2 , then find the value of (4x^(4) + 1)/(4x^(2))
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- Find the square root of 4^(6n^(2)) (25)^((a)/(2)) 9^(b^(4)) .
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- (a^(2))/(2) + (b^(3))/(3) - (3c^(3))/(4) + (a^(2))/(3) - (3b^(3))/(4) ...
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- {:("Column" A ,, "Column" B) , ((a+b)^(2) = ,, (a) (x + 1)^(2) ( x-1))...
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