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PEARSON IIT JEE FOUNDATION-EXPRESSIONS AND SPECIAL PRODUCTS -EXAMPLE 2.1
- Add 2x - 3y + z , 5y - x + 7z and 3x - y - 6z.
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Playing Now - Subtract 8p-5q + 7r from 5p- 9q + 3r.
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Play - What should be subtracted from x^(3) - 7x^(2) + 17x + 17 so that the d...
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Play - Multiply (5 - 3x - 4x^(2)) with 2x-3
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Play - (a) Expand (x+4) (x+7) (b) Expand (x+2) (x-5).
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Play - Expand (x + 3) (x - 2) (x + 6).
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Play - Expand (3x + 4y)^(2).
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Play - If x + (1)/(x) = 3 , then find the value of x^(2) + (1)/(x^(2)).
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Play - Expand (5x-9y)^(2)
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Play - If x - (1)/(x) = 5 , then find the value of x^(2) + (1)/(x^(2)).
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Play - If Y + (1)/(Y) = -2 , then find the value of Y^(50) - (1)/(Y^(50)).
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Play - If x^(2) - y^(2) = 12 xy , then find the value of (x^(2))/(y^(2)) + (y...
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Play - Simplify (3x + 4y)^(2) + (3x-4y)^(2).
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Play - Simplify (11x + 3y)^(2) - (11x - 3y)^(2).
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Play - Simplify: (3x - 7y) (5x + 2y)
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Play - Factorise 49x^(2) - 16y^(2).
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Play - (a) Factorise : x^(2) - (z-5)x - 5z (b) Factorise : x^(2) + x - y + ...
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Play - (a) Factorise : 9x^(2) - 24 xy + 16y^(2) (b) Factorise : 25x^(2) + (...
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Play - Divide 18x^(4) - 27 x^(3) + 6x by 3x.
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Play - Divide 10x^(3) + 41x^(2) - 4x - 15 by 5x + 3.
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