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The wavelength lambda(e) of an electron ...

The wavelength `lambda_(e)` of an electron and `lambda_(p)` of a photon of same energy E are related by………………

A

`lambda_(p) prop lambda_(e)`

B

`lambda_(p) prop sqrt(lambda_(e))`

C

`lambda_(p) prop (1)/(sqrt(lambda_(e)))`

D

`lambda_(p) prop lambda_(e)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
de Broglie wavelength of electron, `lambda_(e) = (h)/(sqrt(2mE))`
`therefore" ""i.e." lambda_(e) prop (1)/(sqrt(E)) rArr lambda_(e)^(2) prop (1)/(E)" "…(1)`
de-Broglie wavelength of proton
`lambda_(p) = (hc)/(E)`
`lambda_(P) prop (1)/(E)" "...(2)`
From (1) and (2)
`lambda_(e)^(2) prop lambda_(p)" ""i.e.", lambda_(p) prop lambda_(e)^(2)`
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