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In the Bohr's orbit, what is the ratio o...

In the Bohr's orbit, what is the ratio of total kinetic energy and total energy of the electron

A

`-2`

B

`-1`

C

`+2`

D

`0`

Text Solution

Verified by Experts

The correct Answer is:
B
K.E. = `1/2 mv^2, P.E. = - (Ze^2)/r`
and electrostatic force = centrifugal force
`(Ze^2)/(r^2) = (mv^2)/r`
or `(Ze^2)/(r ) = mv^2`
or `PE = -mv^2`
`:. ` Total energy ` = 1/2 mv^2 + (-mv^2) = -1/2 mv^2`
`:. ("K.E.")/("Total energy") = (1/2 mv^2)/(-1/2 mv^2) = -1`
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Knowledge Check

  • In the Bohr's orbit, what is the ratio of total kinetic energy and the total energy of the electron ?

    A
    `-1`
    B
    `-2`
    C
    `+1`
    D
    `+2`

  • In the Bohr's orbit, what is the ratio of total kinetic energy and the total energy of the electron?

    A
    `-1`
    B
    `-2`
    C
    `+1`
    D
    `+2`

  • The ratio of the kinetic energy to the total energy of an electron in a Bohr orbit is

    A
    `-1`
    B
    `2`
    C
    `1:1`
    D
    None of these

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