Benzoic acid reacts with `LiAIH_4` to give

Options

A. Ethylbenzene
B. Methanzene
C. Phenol
D. Benzyl alcohol

Explanation

To solve the problem of what benzoic acid reacts with lithium aluminum hydride (LiAlH4) to produce, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is benzoic acid, which has the chemical formula C6H5COOH. It consists of a benzene ring (C6H5) attached to a carboxylic acid group (COOH).

2. **Understand the Reducing Agent**:
- Lithium aluminum hydride (LiAlH4) is a strong reducing agent. It is known to reduce carboxylic acids, aldehydes, ketones, and esters to their corresponding alcohols.

3. **Determine the Reaction**:
- When benzoic acid reacts with LiAlH4, the carboxylic acid group (COOH) will be reduced. The reaction does not affect the benzene ring; it only reduces the carboxylic acid to an alcohol.

4. **Write the Product**:
- The reduction of the carboxylic acid (COOH) group in benzoic acid leads to the formation of benzyl alcohol. The structure of benzyl alcohol is C6H5CH2OH, where the COOH group is converted to a CH2OH group.

5. **Final Product**:
- Therefore, the product of the reaction between benzoic acid and lithium aluminum hydride is benzyl alcohol.

### Conclusion:
Benzoic acid reacts with LiAlH4 to give benzyl alcohol (C6H5CH2OH).

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