A pair of compounds which has odd electrons in the group `NO,CO,CIO,N_(2),SO_(2) and O_(3) ` are

Options

A. `No and CIO_(2)`
B. `CO and SO_(2)`
C. `CIO_2 and CO`
D. `SO_(2) and O_(3)`

Answer

To solve the problem of identifying the pair of compounds that have odd electrons from the given list (NO, CO, ClO, N₂, SO₂, and O₃), we will analyze the total number of valence electrons for each compound.

### Step 1: Analyze each compound for odd/even electrons

1. **NO (Nitric Oxide)**:
- Nitrogen (N) has 5 valence electrons.
- Oxygen (O) has 6 valence electrons.
- Total = 5 + 6 = 11 electrons (odd).

2. **CO (Carbon Monoxide)**:
- Carbon (C) has 4 valence electrons.
- Oxygen (O) has 6 valence electrons.
- Total = 4 + 6 = 10 electrons (even).

3. **ClO (Chlorine Monoxide)**:
- Chlorine (Cl) has 7 valence electrons.
- Oxygen (O) has 6 valence electrons.
- Total = 7 + 6 = 13 electrons (odd).

4. **N₂ (Nitrogen Gas)**:
- Each Nitrogen (N) has 5 valence electrons.
- Total for N₂ = 5 + 5 = 10 electrons (even).

5. **SO₂ (Sulfur Dioxide)**:
- Sulfur (S) has 6 valence electrons.
- Each Oxygen (O) has 6 valence electrons.
- Total = 6 + 6 + 6 = 18 electrons (even).

6. **O₃ (Ozone)**:
- Each Oxygen (O) has 6 valence electrons.
- Total for O₃ = 6 + 6 + 6 = 18 electrons (even).

### Step 2: Identify the compounds with odd electrons
From the analysis:
- NO has 11 electrons (odd).
- ClO has 13 electrons (odd).
- CO, N₂, SO₂, and O₃ have even electrons.

### Conclusion
The pair of compounds that have odd electrons are **NO and ClO**.