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The bond order in N(2)^(+) ion is ....

The bond order in `N_(2)^(+)` ion is __________.

A

1.5

B

`3.0`

C

2.5

D

`2.0`

Text Solution

Verified by Experts

The correct Answer is:
C
`N_(2)^(+)=7+7-1=13` electrons
Configuration is
`sigma 1s^(2), sigma^(* *)1s^(2), sigma2s^(2), sigma^(* *) 2s^(2), pi 2p_(x)^(2), =pi 2p_(y)^(2), sigma2p_(z)^(1)`
Bond order `=(nb-na)/(2)`
`=(1)/(@) (9-4)=(1)/(2)xx5=2.5`
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Knowledge Check

  • The bond order in N_(2) ^(-) is

    A
    2
    B
    `2.5`
    C
    `1.5`
    D
    3

  • The bond order in O_(2)^(+) is

    A
    2
    B
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    C
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    D
    3

  • The bond order in He_2^(+) ions is :

    A
    0.5
    B
    `1.0`
    C
    1.5
    D
    `2.0`

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