Home
Class 12
PHYSICS
A conducting rod of length l is hinged a...

A conducting rod of length l is hinged at point O. It is a free to rotate in a verical plane. There exists a uniform magnetic field B in horizontal direction. The rod is released from the position shown. The potential difference between the two ends of the rod is proportional to

A

`l^(3//2)`

B

`l^(2)`

C

`sintheta`

D

`(sintheta)^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
A, D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Linked Comprehension)|19 Videos
  • ELECTROMAGNETIC INDUCTION

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Matrix-Match)|8 Videos
  • ELECTROMAGNETIC INDUCTION

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Single Correct Choice Type)|45 Videos
  • ELECTRIC POTENTIAL

    RESNICK AND HALLIDAY|Exercise (PRACTICE QUESTIONS) Integer Type|1 Videos
  • ELECTROMAGNETIC OSCILLATIONS AND ALTERNATING CURRENT

    RESNICK AND HALLIDAY|Exercise Practice Questions (Integer)|7 Videos

Similar Questions

Explore conceptually related problems

A conducting rod of length l is hinged at point O . It is free to rotate in vertical plane. There exists a uniform magnetic field vecB in horizontal direction. The rod is released from position shown in the figure. Potential difference between two ends of the rod is proportional to

A rod of length l rotates with a uniform angular velocity omega about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the two ends of the lrod is

Knowledge Check

  • A conducting rod of length l is higed at point O. It is free to rotate in a vertical plane. There exists a uniform magnetic field vec(B) in horizontal direction. The rod is released from the position shown in figure. Potential difference between the two ends of the rod is proportional to

    A
    `l^(3//2)`
    B
    `l^(2)`
    C
    `sin theta`
    D
    `(sin theta)^(1//2)`
  • A rod of length 1 rotates with a small but uniform angular velocity u about its perpendicular bisector. a uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the two ends of the rod is:

    A
    zero
    B
    `1/2 omegaBI^(2)`
    C
    `omega BI^(2)`
    D
    `2omegaBI^(2)`
  • A conducting rod rotates with a constant angular velocity 'omega' about the axis which passes through point 'O' and perpendicular to its length . A uniform magnetic field 'B' exists parallel to the axis of the rotation . Then potential difference between the two ends of the rod is :-

    A
    `6B omegal^(2)`
    B
    `B omega l^(2)`
    C
    `10B omega l^(2)`
    D
    Zero
  • Similar Questions

    Explore conceptually related problems

    A rod of length l rotates with a small but uniform angular velocity omega about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the centre of the rod and an end is

    A conducting rod of length l is falling with a velocity v perpendicular to a uniform horizontal magnetic field B. The potential difference between the two ends will be

    A conducing rod of length l is falling with a velocity v perpendicular to a unifrorm horizontal magnetic field B . The potential difference between its two ends will be

    A metal rod of length L is placed normal to a magnetic field and rotated through one end of rod in circular path with frequency f. The potential difference between it ends will be-

    A metal rod of length l pivoted at is upper end. It is released from a horizontal position. There is a uniform magnetic field _|_ to its plane of rotation. When it becomes vertical, the p.d. across its ends is proportional to