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A rod of length b moves with a constant ...

A rod of length b moves with a constant velocity v in the magnetic field of a straight long conductor that carries a current I as shown in the below figure. The emf induced in the rod is

A

`(mu_(0)Iv)/(2pi)tan^(-1)(a/b)`

B

`(mu_(0)Iv)/(2pi)ln(1+a/b)`

C

`(mu_(0)Ivsqrt(ab))/(2pi(a+b))`

D

`(mu_(0)Iv(a+b))/(4piab)`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • A rod AB moves with a uniform velocity v in a uniform magnetic field as shown in figure.

    A
    The rod becomes electrically charged
    B
    The end A becomes positively charged
    C
    The end B becomes positively charged
    D
    The rod becomes hot because of Joule heating

  • A small conducting rod of length l, moves with a uniform velocity v in a uniform magnetic field B as shown in fig __

    A
    Then the end X of the rod becomes positively charged
    B
    The end Y of the rod becomes positively charged
    C
    The entire rod is unevenly charged
    D
    The rod becomes hot due to joule heating

  • A cionducing rod moves with constant velocity v perpendicular to the straight wire carrying a current I as shown compute that the emf generated between the ends of the rod

    A
    `(mu_(0)vIl)/(pir)`
    B
    `(mu_(0)vIl)/(2pir)`
    C
    `(2mu_(0)vIl)/(pir)`
    D
    `(mu_(0)vIl)/(4pir)`

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