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intx^(6) dx = ?...

`intx^(6) dx = ?`

A

`7x^(7) +C`

B

`(x^(7))/(7) + C`

C

`6x^(5) + C`

D

`6x^(7) + C`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the integral \( \int x^6 \, dx \), we will use the power rule for integration. The power rule states that: \[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \] where \( n \) is any real number except \(-1\), and \( C \) is the constant of integration. ### Step-by-step Solution: 1. **Identify \( n \)**: In our case, \( n = 6 \). 2. **Apply the power rule**: According to the power rule, we will increase the exponent by 1 and divide by the new exponent: \[ \int x^6 \, dx = \frac{x^{6+1}}{6+1} + C \] 3. **Calculate the new exponent**: \[ 6 + 1 = 7 \] 4. **Substitute back into the equation**: \[ \int x^6 \, dx = \frac{x^7}{7} + C \] 5. **Final answer**: Thus, the integral of \( x^6 \) with respect to \( x \) is: \[ \int x^6 \, dx = \frac{x^7}{7} + C \] ### Summary of the Solution: \[ \int x^6 \, dx = \frac{x^7}{7} + C \]
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Knowledge Check

  • intx^(5/3)dx = ?

    A
    `3/5x^(2/3) + C`
    B
    `8/3 x^(8/3) +C`
    C
    `3/8 x^(8/3)+ C`
    D
    `5/3x^(8/3) + C`
  • intxe^(x)dx=?

    A
    `e^(x)(1-x)+C`
    B
    `e^(x)(x+1)+C`
    C
    `e^(x)(x-1)+C`
    D
    none of these
  • intxe^(2x)dx=?

    A
    `(1)/(2)xe^(2x)+(1)/(4)e^(2x)+C`
    B
    `(1)/(2)xe^(2x)-(1)/(4)e^(2x)+C`
    C
    `2xe^(2x)+4e^(2x)+C`
    D
    none of these
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