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xdy=(x+y)dx...

`xdy=(x+y)dx`

Text Solution

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The correct Answer is:
`y=xlog|x|+Cx`
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Solve xdy=y(xy+1)dx

If xdy=y(dx+ydy);y(1)=1 and y(x)>0 then what is y(-3) equal to?

Knowledge Check

  • If xdy=y (dx+ydy),y(1)=1 and y(x) gt 0, then y(-3) is equal to

    A
    3
    B
    2
    C
    1
    D
    0

  • The solution of the differential equation xdy+(y)/(x)dx=(dx)/(x) is (where, c is an arbitarary constant)

    A
    `y=1+ce^(1//x)`
    B
    `y=ce^(1//x)`
    C
    `y=ce^(1//x)-1`
    D
    `xy=1-ce^(1//x)`

  • If the curve satisfying differential equation xdy=(y+x^(3))dx passes through (1, 1), then the equation to the curve is

    A
    `y^(2)=x^(3)-x`
    B
    `y=x^(2)-x`
    C
    `2y=x^(3)`
    D
    `2y=x^(3)+x`

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