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int 1/(1+cosx) dx=...

`int 1/(1+cosx) dx=`

A

`-cot x + cosec x + C`

B

`cot x - cosec x + C`

C

`cot x + cosec x + C`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A

`I = int{(1)/((1+cosx)) xx ((1-cosx))/((1-cosx))} dx = int((1-cosx))/(sin^(2)x) dx`
`= {(-1)/(sin^(2)x) - (cosx)/(sin^(2)x)} dx = int(cosec^(2)x - cosec x cot x ) dx`.
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