Let `S_(1)` and `S_(2)` be the two switches and let their probabilities of working be given by `P(S_(1))=⅘` and `P(S_(2))=.^(9)//_(10)`. Find the probability that the current flows from the terminal a to terminal A to terminal B when `S_(1)` and `S_(2)` are installed in series, shown as follows :
Text Solution
Verified by Experts
The correct Answer is:
`18/25`
P( current flows from A to B) `=P (S_(1)" is closed and "S_(2)" is closed")` `=P (S_(1) and S_(2))=P (S_(1))xxP_(S_(2))`.
" Oxidation state of terminal Sulphur in S_(2)O_(3)^(-2) is "
Let S_(1) and S_(2) be the two slits in Young's double-slit experiment. If central maxima is observed at P and angle /_ S_(1) P S_(2) = theta , then fringe width for the light of wavelength lambda will be
Let S_(1) and S_(2) be the two slits in Young's double-slit experiment. If central maxima is observed at P and angle /_ S_(1) P S_(2) = theta , then fringe width for the light of wavelength lambda will be (assume theta to be a small angle)
If S_(1),S_(2) andS _(3) be respectively the sum of n,2n and 3n terms of a G.P.prove that S_(1)(S_(3)-S_(2))=(S_(2)-S_(1))^(2)
Only three students, S_(1),S_(2) and S_(3) appear at a compettive examination. The probability of S_(1) coming first is 3 times that of S_(2) and the probability of S_(2) coming first is three times that of S_(3) . Find the probability of each coming first. Also find the probability that S_(1) or S_(2) comes first.
In the circuit shown switches S_(1) and S_(2) have been closed for 1 sec and S_(2) remained open.Just after 1 second is over switch S_(2) is closed and S_(1),S_(3) are opened.Find after that instant The charge on the upper plate of the capacitor as function of time taking the instant of switching on of S_(2) and switching off all time switches to be t=0 is q=x xx10^(-2)cos (t+pi/4) .Findout value of x .
Gourang made an electric circuit with three bulbs B_(1), B_(2) and B_(3) a cell and two switches S_(1) and S_(2) as shown in figure. He notes his observation when (a) S_(1) is closed and S_(2) is open, (b) S_(2) is closed and S_(1) is open. He also found that a bulb whose failure made the circuit 'open' irrespective of the status of S_(1) and S_(2) . What are his observation.
If S_(1),S_(2),S_(3) be respectively the sums of n,2n and 3n terms of a G.P.,prove that S_(1)(S_(3)-S_(2))=(S_(2)-S_(1))^(2)
