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In the given figure, D is a point on sid...

In the given figure, D is a point on side BC of a `DeltaABC` and E is a point such that CD = DE.
Prove that `AB+ACgtBE`.

Text Solution

Verified by Experts

`ABA+ACgtBC`
`rArr" "AB+ACgtBD+DC=BD+DEgtBE.`
`therefore" "(AB+AC)gtBE.`
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