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16 g of oxygen has same number of molecu...

16 g of oxygen has same number of molecules as in

A

16 g of CO

B

28 g of `N_(2)`

C

14 g of `N_(2)`

D

1.0 g of `H_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C, D
Number of molecules `=("mass")/("molar mass") xx N_(A)`
Number of molecules, in 16 g oxygen
`=16/32 xx N_(A) = N_(A)/2`
In 16 g of CO `=16/28 xx N_(A) = N_(A)/1.75`
In 28g of `N_(2) = 28/28 xx N_(A) = N_(A)`
In 14 g of `N_(2) = 14/28 xx N_(A) = N_(A)/2`
In 1 g of `H_(2) =1/2 N_(A) = N_(A)/2`
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