Home
Class 12
PHYSICS
Why the electric field at the outer sur...

Why the electric field at the outer surface of a hollow charged conductor is normal to the surface?

Text Solution

Verified by Experts

The electrostatic field be normal to the surface at every point of a charge conductor. Electric field inside the conductor is always zero. The electric lines of force exert lateral pressure on each other leads to explain repulsion between like charges.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise [Set-III]|6 Videos
  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise PHYSICS (Theory) [SET - I]|32 Videos
  • XII BOARDS

    XII BOARDS PREVIOUS YEAR|Exercise SET-III, DELHI BOARD|8 Videos
  • SAMPLE PAPER 2019

    XII BOARDS PREVIOUS YEAR|Exercise SECTION D|6 Videos

Similar Questions

Explore conceptually related problems

Show that the electric field at the surface of a charged conductor is proportional to the surface charge density.

Show that the electric field at the surface of a charged conductor is given by oversetto E = ( sigma )/( 60 ) hat n , where sigma is the surface charge density and hatn is a unit vector normal to the surface in the outward direction.

Knowledge Check

  • The electric field intensity on the surface of a charged conductor is

    A
    zero
    B
    directed normally to the surface
    C
    directed tangentially to the surface
    D
    directed along `45^(@)` to the surface
  • The electric field intensity on the surface of a charged conductor is

    A
    zero
    B
    directed normally to the surface
    C
    directed tangentially to the surface
    D
    directed along `45^(@)` to the surface
  • Across the surface of a charged conductor

    A
    field is continuous
    B
    potential is continuous
    C
    field is discontinuous
    D
    potential is discontinuous
  • Similar Questions

    Explore conceptually related problems

    What is an equipotential surface ? Show that the electric field at a point on the surface of a charged conductor or just outside it is perpendicular to the surface ?

    Show that the electric field at the surface of a charged conductor is given by vecE = (sigma)/(epsi_(0)) hatn , where sigma is the surface charge density and hatn is a unit vector normal to the surface in the outward direction .

    What is the direction of the electric field at the surface of a charged conductor having charge density sigma <0?

    Across the surface of a charged conductor, the electric

    Electric field intensity at a point a hollow charged spherical conductor