Write the half reaction for the reaction
`2Fe^(+3) + 2I^(-) to 2Fe^(+2) + I_(2)`

Explanation

To write the half-reactions for the redox reaction \(2Fe^{+3} + 2I^{-} \rightarrow 2Fe^{+2} + I_{2}\), we will follow these steps:

### Step 1: Identify the oxidation states
- For \(Fe^{+3}\), the oxidation state is +3.
- For \(Fe^{+2}\), the oxidation state is +2.
- For \(I^{-}\), the oxidation state is -1.
- For \(I_{2}\), the oxidation state is 0.

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