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0.144 g of pure FeC(2)O(4) was dissolved...

0.144 g of pure `FeC_(2)O_(4)` was dissolvedin dilute `H_(2)SO_(4)` and the solution was diluted to 100 ml . What volume in ml of 0.1 M `KMnO_(4)` will be needed to oxidise `FeC_(2)O_(4)` solution

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1.44 g of pure Fec_(2)O_(4) was dissolved in dil H_(2)SO_(4) and th solution diluted to 100 cm^(3) calculate the volume of 0.01 M KMnO_(4) requiredto oxidise FeC_(2)O_(4) solution completely

1.44 g of pure Fec_(2)O_(4) was dissolved in dil H_(2)SO_(4) and th solution diluted to 100 cm^(3) calculate the volume of 0.01 M KMnO_(4) requiredto oxidise FeC_(2)O_(4) solution completely

Knowledge Check

  • What volume of 0.1 M KMnO_(4) is needed to oxidize 100 mg of FeC_(2)O_(4) in acid solution ?

    A
    `4.1` ml
    B
    `8.2` ml
    C
    `10.2` ml
    D
    `4.6` ml

  • What volume of 0.1M KMnO_(4) is needed to oxidize 100 mg of FeC_(2)O_(4) in acid solution ?

    A
    4.1 mL
    B
    8.2 mL
    C
    10.2 mL
    D
    4.6 mL

  • 20 ml of '20 vol' H_(2)O_(2) solution is diluted to 80 ml. The final volume strength of solution is

    A
    80 vol'
    B
    25 vol'
    C
    5 vol'
    D
    8 vol'

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    0.2828 g of iron wire was dissolved in excess dilute H_(2)SO_(4) and the solution was made upto 100mL. 20mL of this solution required 30mL of N/(30)K_(2)Cr_(2)O_(7) solution for exact oxidation. Calculate percent purity of Fe in wire.

    1g pure iron is dissolved in excess of H_(2)SO_(4) . The clear filtrate is made up 100 mL. 10mL of this solution is treated with 0.1 M KMnO_(4) solution till whole of the Fe^(2+) ions are oxidised to Fe^(3+) ions. Now 0.2 g Fe_(2)(SO_(4))_(3) is dissolved in it. the solution is now treated with Zn and H_(2)SO_(4) . The volume of KMnO_(4) needed to convert Fe^(2+) ions to Fe^(3+) ions in 100 mL original solution is:

    1g pure iron is dissolved in excess of H_(2)SO_(4) . The clear filtrate is made up 100 mL. 10mL of this solution is treated with 0.1 M KMnO_(4) solution till whole of the Fe^(2+) ions are oxidised to Fe^(3+) ions. Now 0.2 g Fe_(2)(SO_(4))_(3) is dissolved in it. the solution is now treated with Zn and H_(2)SO_(4) . The volume of 0.1 M KMnO_(4) used after reducing the solution mixture with Zn+H_(2)SO_(4) is:

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    The number of moles of KMnO_(4) required to oxidise 2 mol of FeC_(2)O_(4) is acidin medium is :-

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