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In Delta ABC, if r(1) lt r(2) lt r(3), t...

In `Delta ABC`, if `r_(1) lt r_(2) lt r_(3)`, then find the order of lengths of the sides

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To solve the problem, we need to find the order of the lengths of the sides of triangle ABC given the condition \( r_1 < r_2 < r_3 \). Here’s the step-by-step solution: ### Step 1: Understand the relationship between inradii and sides In a triangle, the inradii \( r_1, r_2, r_3 \) are given by the formulas: - \( r_1 = \frac{\Delta}{s - a} \) - \( r_2 = \frac{\Delta}{s - b} \) - \( r_3 = \frac{\Delta}{s - c} \) where \( \Delta \) is the area of the triangle, and \( s \) is the semi-perimeter defined as \( s = \frac{a + b + c}{2} \). ### Step 2: Set up the inequalities Given the condition \( r_1 < r_2 < r_3 \), we can write: \[ \frac{\Delta}{s - a} < \frac{\Delta}{s - b} < \frac{\Delta}{s - c} \] ### Step 3: Invert the inequalities Since \( \Delta > 0 \) (the area of the triangle is positive), we can safely invert the inequalities: \[ \frac{1}{s - a} > \frac{1}{s - b} > \frac{1}{s - c} \] ### Step 4: Cross-multiply to eliminate the fractions Cross-multiplying gives us: \[ s - b > s - a > s - c \] ### Step 5: Simplify the inequalities By simplifying the inequalities, we get: \[ -a > -b > -c \] ### Step 6: Multiply by -1 Multiplying the entire inequality by -1 (and reversing the order of the inequalities) gives: \[ b > a > c \] ### Conclusion Thus, the order of the lengths of the sides of triangle ABC is: \[ c < a < b \]

To solve the problem, we need to find the order of the lengths of the sides of triangle ABC given the condition \( r_1 < r_2 < r_3 \). Here’s the step-by-step solution: ### Step 1: Understand the relationship between inradii and sides In a triangle, the inradii \( r_1, r_2, r_3 \) are given by the formulas: - \( r_1 = \frac{\Delta}{s - a} \) - \( r_2 = \frac{\Delta}{s - b} \) - \( r_3 = \frac{\Delta}{s - c} \) ...
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