Home
Class 11
PHYSICS
Two balls of different masses are thrown...

Two balls of different masses are thrown vertically upwards with the same speed . They pass through the point of projection in their downward motion with the same speed ( Neglect air resistance ).

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of two balls of different masses thrown vertically upwards with the same initial speed and determine if they pass through the point of projection during their downward motion with the same speed. ### Step-by-Step Solution: 1. **Identify the Given Information:** - Two balls are thrown vertically upwards. - Both balls have different masses. - Both balls are thrown with the same initial speed. - We need to analyze their motion as they return to the point of projection. 2. **Understand the Motion of the Balls:** - When an object is thrown vertically upwards, it will rise until it reaches its maximum height, where its velocity becomes zero. - After reaching the maximum height, the object will fall back down under the influence of gravity. 3. **Apply the Equations of Motion:** - The equations of motion for uniformly accelerated motion (under gravity) are independent of mass. The key equation we can use is: \[ v^2 = u^2 + 2as \] where: - \( v \) is the final velocity, - \( u \) is the initial velocity, - \( a \) is the acceleration (which is \(-g\) for upward motion), - \( s \) is the displacement. 4. **Analyze the Upward Motion:** - Both balls are thrown upwards with the same initial speed \( u \). - They will rise until their velocity becomes zero at the maximum height. The time taken to reach the maximum height and the height reached will depend on the initial speed and acceleration due to gravity, but not on mass. 5. **Analyze the Downward Motion:** - As the balls fall back down, they will pass through the point of projection (the starting point) with the same speed they were thrown upwards. - Since both balls were thrown with the same initial speed and are subject to the same gravitational acceleration, they will return to the point of projection with the same speed. 6. **Conclusion:** - Since the equations of motion do not depend on mass, both balls will indeed pass through the point of projection during their downward motion with the same speed. - Therefore, the statement is **true**. ### Final Answer: The statement is true; both balls will pass through the point of projection in their downward motion with the same speed. ---

To solve the problem, we need to analyze the motion of two balls of different masses thrown vertically upwards with the same initial speed and determine if they pass through the point of projection during their downward motion with the same speed. ### Step-by-Step Solution: 1. **Identify the Given Information:** - Two balls are thrown vertically upwards. - Both balls have different masses. - Both balls are thrown with the same initial speed. ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS ENGLISH|Exercise Interger type|3 Videos
  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS ENGLISH|Exercise Fill in the blanks|4 Videos
  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS ENGLISH|Exercise Single correct anwer type|14 Videos
  • MISCELLANEOUS VOLUME 2

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|10 Videos

Similar Questions

Explore conceptually related problems

Two balls of different masses (one lighter and other heaver) are thrown vertically upwards with the same speed. Which one will pass through the point of projection in the downward direction with greater speed?

Two balls of different masses are thrown vertically upward with same initial velocity. Height attained by them are h_1 and h_2 respectively. What is h_1//h_2 ?

Knowledge Check

  • A ball of mass M is thrown vertically upwards. Another ball of mass 2M is thrown at an angle theta with the vertical. Both of them stay in air for the same period of time. The heights attained by the two are in the ratio

    A
    `1:2`
    B
    `2:1`
    C
    `1:1`
    D
    `1: cos theta`
  • Similar Questions

    Explore conceptually related problems

    Two balls are thrown simultaneously, A vertically upwards with a speed of 20 m/s from the ground, and B vertically downwards from a height of 40 m with the same speed along the same line of motion. At what point do the two balls collide? Take g = 9.8 m//s^(2) .

    If a ball is thrown vertically upwards with speed u , the distance covered during the last t second of its ascent is

    A person standing near the edge of the top of a building throws two balls A and B. The ball A is thrown vertically upward and B is thrown vertically downward with the same speed. The ball A hits the ground with speed v_A and the ball B hits the ground wiht a speed v_B . We have

    Two balls of different masses are thrown in air with different velocities. While they are in air acceleration of centre of mass of the system. (neglect air resistance)?

    A ball is thrown vertically upward with a speed of 20 m/s. Draw a graph showing the velocity of the ball as a function of time as it goes up and then comes back.

    A particle is projected vertically upwards with a speed of 16ms^-1 . After some time, when it again passes through the point of projection, its speed is found to be 8ms^-1 . It is known that the work done by air resistance is same during upward and downward motion. Then the maximum height attained by the particle is (take g=10ms^-2 )

    A body is projected vertically upward with speed 40m/s. The distance travelled by body in the last second of upward journey is [take g=9.8m/s^(2) and neglect of air resistance]:-