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A particle moves in a circle of radius R...

A particle moves in a circle of radius R. In half the period of revolution its displacement is ………… and distance covered is ………. .

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To solve the problem, we need to determine the displacement and distance covered by a particle moving in a circle of radius R after completing half of its period of revolution. ### Step-by-Step Solution: 1. **Understanding the Motion**: - The particle is moving in a circular path with a radius \( R \). - Half of the period of revolution means the particle has moved from one point on the circle to the point directly opposite it. 2. **Calculating the Distance Covered**: - The distance covered by the particle in half a revolution is half the circumference of the circle. - The circumference \( C \) of a circle is given by the formula: \[ C = 2\pi R \] - Therefore, the distance covered in half the revolution is: \[ \text{Distance} = \frac{C}{2} = \frac{2\pi R}{2} = \pi R \] 3. **Calculating the Displacement**: - Displacement is defined as the shortest distance between the initial and final positions of the particle. - When the particle moves half the circle, its initial position and final position are at opposite ends of the diameter. - The displacement, which is the length of the diameter, is given by: \[ \text{Displacement} = 2R \] ### Final Answers: - **Displacement**: \( 2R \) - **Distance Covered**: \( \pi R \)

To solve the problem, we need to determine the displacement and distance covered by a particle moving in a circle of radius R after completing half of its period of revolution. ### Step-by-Step Solution: 1. **Understanding the Motion**: - The particle is moving in a circular path with a radius \( R \). - Half of the period of revolution means the particle has moved from one point on the circle to the point directly opposite it. ...
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