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Statement 1: In the purely resistive ele...

Statement 1: In the purely resistive element of a series LCR, ac circuit the maximum value of rms current increase with increase in the angular frequency of the applied emf.
Statement 2: `I_(max)=(epsilon_(max))/(Z), Z=sqrt(R^(2)+(omega L-(1)/(omega C)^(2)))`,
where `(I_(max))` is the peak current in a cycle.

A

Statement 1 is true, statement 2 is true, Statement 2 is the correct explanation for statement 1.

B

Statemet 1 is True, Statement 2 is true , Statement 2 is NOT the correct explanation for Statement 1

C

Statement 1 is True, Statement 2 is False.

D

Statement 1 is False, Statement 2 is true

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the given statements, we need to understand the behavior of a series LCR circuit under alternating current (AC) conditions. Let's break down the statements and derive the necessary conclusions step by step. ### Step 1: Understanding the Circuit In a series LCR circuit, we have a resistor (R), an inductor (L), and a capacitor (C) connected in series. The total impedance (Z) of the circuit is given by: \[ Z = \sqrt{R^2 + \left( \omega L - \frac{1}{\omega C} \right)^2} \] where: - \( \omega \) is the angular frequency of the applied EMF. ### Step 2: Analyzing Statement 1 **Statement 1:** "In the purely resistive element of a series LCR circuit, the maximum value of the RMS current increases with an increase in the angular frequency of the applied EMF." - In a purely resistive circuit, the impedance \( Z \) is simply \( R \). - The maximum current \( I_{\text{max}} \) can be expressed as: \[ I_{\text{max}} = \frac{E_{\text{max}}}{Z} \] - As the frequency increases, the reactive components (inductive and capacitive) do not contribute to the impedance in a purely resistive circuit. Therefore, the impedance remains constant at \( R \). - Thus, the maximum current does not increase with frequency; it remains constant. **Conclusion for Statement 1:** This statement is **false**. ### Step 3: Analyzing Statement 2 **Statement 2:** "I_{\text{max}} = \frac{E_{\text{max}}}{Z}, Z = \sqrt{R^2 + \left( \omega L - \frac{1}{\omega C} \right)^2}." - This equation is indeed correct for a series LCR circuit. - The expression for impedance \( Z \) is accurate and reflects the total opposition to current flow in the circuit. - However, the statement does not directly address the behavior of current with respect to frequency in a purely resistive circuit. **Conclusion for Statement 2:** The statement is **true** in terms of the formula provided, but it does not apply to the context of purely resistive elements as described in Statement 1. ### Final Conclusion - **Statement 1:** False - **Statement 2:** True

To analyze the given statements, we need to understand the behavior of a series LCR circuit under alternating current (AC) conditions. Let's break down the statements and derive the necessary conclusions step by step. ### Step 1: Understanding the Circuit In a series LCR circuit, we have a resistor (R), an inductor (L), and a capacitor (C) connected in series. The total impedance (Z) of the circuit is given by: \[ Z = \sqrt{R^2 + \left( \omega L - \frac{1}{\omega C} \right)^2} \] where: - \( \omega \) is the angular frequency of the applied EMF. ...
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