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In an ac circuit shown in fig , the supp...

In an ac circuit shown in fig , the supply voltage has a constant rms value v but variable frequency f. At resonance, the circuit

A

has current I given by `I=(V)/(R )`

B

has a resonance frequenv=cy 500 Hz

C

has a voltage across the capacitor which is `180^(@)` out of phase with that across the inductor

D

Has a current given by `I=(V)/(sqrt(R^(2)+((1)/(pi)+(1)/(pi))^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A, C
`f_(res)=(1)/(2 pi sqrt(LC)) = (1)/(2 pi sqrt(1/(pi) xx(1)/(pi) xx 10^(-6)) = 500 Hz`
At resonace, Z=R,
so current `I=V/Z = V/R`
When L and C are in sereis, voltage across capacitor and inductor is `18^(@)` out of phase.
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