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The difference in the oxidation numbers ...

The difference in the oxidation numbers of the two types of sulphur atoms in `Na_(2)S_(4)O_(6)` is:

Text Solution

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`S_(4)O_(6)^(2-):O^(ө)-underset(O)underset(||)overset(O)overset(||)Soverset(+5)-overset(0)S-overset(0)S-underset(O)underset(||)overset(O)overset(||)Soverset(+5)-O^(ө)`
So difference in oxidation numbers of two types of `S=(5-0)=5`
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