An excess of `KO_(2)` is placed in a closed container of `CO_(2)`(g). After reaction is completed. Will the gas pressure be same, greater or less than initial value. Explain.

Explanation

To determine whether the gas pressure in a closed container of carbon dioxide (CO₂) will be the same, greater, or less than the initial value after the reaction with excess potassium superoxide (KO₂), we can analyze the chemical reaction and the changes in the number of moles of gas.

### Step-by-Step Solution:

1. **Identify the Reaction**:
The reaction between potassium superoxide (KO₂) and carbon dioxide (CO₂) can be written as:
\[
2 \text{KO}_2 + \text{CO}_2 \rightarrow \text{K}_2\text{CO}_3 + \text{O}_2
...