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The complex number(1+2i)/( 1-i) lies in ...

The complex number`(1+2i)/( 1-i)` lies in the Quadrant number

A

First quadrant

B

Second quadrant

C

Thrid quadrant

D

Fourth quadrant

Text Solution

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The correct Answer is:
To determine in which quadrant the complex number \( z = \frac{1 + 2i}{1 - i} \) lies, we will follow these steps: ### Step 1: Write down the complex number We start with the complex number: \[ z = \frac{1 + 2i}{1 - i} \] ### Step 2: Multiply by the conjugate of the denominator To simplify \( z \), we multiply the numerator and the denominator by the conjugate of the denominator, which is \( 1 + i \): \[ z = \frac{(1 + 2i)(1 + i)}{(1 - i)(1 + i)} \] ### Step 3: Simplify the denominator The denominator simplifies as follows: \[ (1 - i)(1 + i) = 1^2 - i^2 = 1 - (-1) = 1 + 1 = 2 \] ### Step 4: Simplify the numerator Now, we simplify the numerator: \[ (1 + 2i)(1 + i) = 1 \cdot 1 + 1 \cdot i + 2i \cdot 1 + 2i \cdot i = 1 + i + 2i + 2i^2 \] Since \( i^2 = -1 \), we have: \[ 2i^2 = 2(-1) = -2 \] So the numerator becomes: \[ 1 + i + 2i - 2 = -1 + 3i \] ### Step 5: Combine the results Now we can combine the results: \[ z = \frac{-1 + 3i}{2} \] This can be separated into real and imaginary parts: \[ z = -\frac{1}{2} + \frac{3}{2}i \] ### Step 6: Identify the real and imaginary parts From \( z = -\frac{1}{2} + \frac{3}{2}i \): - The real part is \( -\frac{1}{2} \) (negative) - The imaginary part is \( \frac{3}{2} \) (positive) ### Step 7: Determine the quadrant In the complex plane: - The x-axis represents the real part (horizontal) - The y-axis represents the imaginary part (vertical) Since the real part is negative and the imaginary part is positive, the complex number lies in the **second quadrant**. ### Final Answer Thus, the complex number \( z = \frac{1 + 2i}{1 - i} \) lies in the **second quadrant**. ---
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